Difference between revisions of "Ptolemy's Theorem"

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[[File:Ptolemy's_Theorem.png]]
 
[[File:Ptolemy's_Theorem.png]]
  
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Examining the similar triangles in (c), we have <math>/frac{j}{d} = /frac{b}{p}</math>, so <math>jp = bd</math>
  
<math>x^2</math>
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Examining the similar triangles in (d), we have <math>/frac{j}{c} = /frac{a}{q}</math>, so <math>jq = ac</math>
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So <math>j(p+q) = bd + ac</math>

Revision as of 14:33, 14 January 2016

Ptolemy's Theorem.png

Examining the similar triangles in (c), we have /frac{j}{d}=/frac{b}{p}, so jp=bd

Examining the similar triangles in (d), we have /frac{j}{c}=/frac{a}{q}, so jq=ac

So j(p+q)=bd+ac